কিভাবে Knit Dyeing Recipe ক্যালকুলেশন করবেন - Textile Lab | Textile Learning Blog
কিভাবে ডাইংয়ের Recipe ক্যালকুলেশন করবেন নিম্নে বর্ণনা করা হলঃ

Recipe:

1. Reactive Red Dye = 2.014%

2. Reactive Yellow Dye  = 1.486%

3. Salt = 70%

4.Soda Ash (concentration.20%) = 5 gram/liter

5.Caustic Soda = 1.32%

6.M: L = 1:8

7.Sample Weight. = 5 gram
Stock Solution (In percentages) = 1

Calculation:

1. Required Dye = Shade percentage (%) x Weight of the fabric in gram (gm) / percentage (%) of Stock solution.

so,
Required Reactive Red dye
= (2.014 x 5)/1
= 10.07 g/l

2. Required Reactive Yellow dye
= (1.486 x 5)/1
= 7.43 g/l.

3. For auxiliaries:

We know,
Salt in gram/liter = (Required amount (%) x Sample weight x Liquor Ratio) / 1000

so,
Required Salt = (70 x 5 x 8)/1000 = 2.8 gram.

4. For Soda ash (concentration 20%) :

We know ,
Required amount of solution (mls) = (Gram/liquor required x Weight of substrate x Liquor ratio ) / (10 x concentration (%) of stock solution)

so,
Required amount of soda ash in C.C. = (5 x 5 x 8) / (10 x 20) = 1.0

5. For Caustic soda 

We know ,
Required alkali soln in c.c. = (Required amount (%)  x wt of substrate  x Liquor Ratio )/conversion value from Be. to g/l of alkali

so,
Required caustic soda = (1.32 x5 x8)/441
= 0.12 c.c.

[since 38 °Be.NaOH= 441 gm NaOH 100% per 1lit NaOH soln]

Additional  Water required:
= M:L – (required water to make solution of dyes & auxiliaries)
= (5 x 8) – (10.07+7.431.0+0.12)
= 40 – 18.502
= 21.498

কিভাবে Knit Dyeing Recipe ক্যালকুলেশন করবেন

কিভাবে ডাইংয়ের Recipe ক্যালকুলেশন করবেন নিম্নে বর্ণনা করা হলঃ

Recipe:

1. Reactive Red Dye = 2.014%

2. Reactive Yellow Dye  = 1.486%

3. Salt = 70%

4.Soda Ash (concentration.20%) = 5 gram/liter

5.Caustic Soda = 1.32%

6.M: L = 1:8

7.Sample Weight. = 5 gram
Stock Solution (In percentages) = 1

Calculation:

1. Required Dye = Shade percentage (%) x Weight of the fabric in gram (gm) / percentage (%) of Stock solution.

so,
Required Reactive Red dye
= (2.014 x 5)/1
= 10.07 g/l

2. Required Reactive Yellow dye
= (1.486 x 5)/1
= 7.43 g/l.

3. For auxiliaries:

We know,
Salt in gram/liter = (Required amount (%) x Sample weight x Liquor Ratio) / 1000

so,
Required Salt = (70 x 5 x 8)/1000 = 2.8 gram.

4. For Soda ash (concentration 20%) :

We know ,
Required amount of solution (mls) = (Gram/liquor required x Weight of substrate x Liquor ratio ) / (10 x concentration (%) of stock solution)

so,
Required amount of soda ash in C.C. = (5 x 5 x 8) / (10 x 20) = 1.0

5. For Caustic soda 

We know ,
Required alkali soln in c.c. = (Required amount (%)  x wt of substrate  x Liquor Ratio )/conversion value from Be. to g/l of alkali

so,
Required caustic soda = (1.32 x5 x8)/441
= 0.12 c.c.

[since 38 °Be.NaOH= 441 gm NaOH 100% per 1lit NaOH soln]

Additional  Water required:
= M:L – (required water to make solution of dyes & auxiliaries)
= (5 x 8) – (10.07+7.431.0+0.12)
= 40 – 18.502
= 21.498

কোন মন্তব্য নেই: